I'm going to simplify* and rephrase some chemistry information into terms most of us are more comfortable with. This is my detailed geek explanation behind the general advice I gave in my first post in this thread.
Let's say I make a saturated NaOH solution (roughly a 50% concentration) and cool this solution to normal room temperature. I then put some of that 50% NaOH solution in an open dish and let it sit in the open room air. What I will find is this solution will absorb water vapor from the air if the relative humidity in the air is 10% or higher. **
In other words, the open air has to be as dry or drier than the Mojave Desert before a 50% NaOH solution can't pull water out of the air.
This combination of less than 10% relative humidity (RH) in the air and 50% NaOH solution in the dish, will create what chemists call an "equilibrium." That means the water in the air and the water in the NaOH solution are in balance and are not changing.
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Most homes are usually more humid than 10% RH, even in winter. For example, the air in my house is about 45% RH today. If I put some of that same 50% NaOH solution in an open dish in my house, the NaOH solution would absorb water from the air and become less concentrated.
Eventually when the NaOH solution had absorbed enough water, it would become diluted enough that it will stop absorbing water. At that point, this diluted solution would be in equilibrium with the higher relative humidity in my house. The water in the air and the water in the NaOH solution would be in balance and would not be changing.
I could measure the NaOH concentration of this more dilute solution using a simple chemistry test (for the chem geeks -- I'd titrate the alkali solution with a calibrated acid solution). This test would tell me what NaOH solution concentration is in balance (in equilibrium) with the relative humidity of the air in my house today. If I do the test correctly, it should tell me the NaOH solution concentration is about 30%. **
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The following table shows the NaOH concentrations that are in equilibrium with various amounts of relative humidity --
NaOH concentration, weight % ... Relative humidity, % (RH) **
21% NaOH is in equilibrium with 70% RH
25% NaOH ... 60% RH
28% NaOH ... 50% RH
32% NaOH ... 40% RH
35% NaOH ... 30% RH
40% NaOH ... 20% RH
48% NaOH ... 10% RH
To give one example of what this means --
Many people use a 28% lye concentration (aka "full water") to make soap. This "full water" NaOH solution will absorb water from the air any time the relative humidity is higher than 50%. A 28% lye solution will not absorb water vapor if the air is drier than that (less than 50% RH).
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* A BIG simplification in this explanation is that I'm totally ignoring the reaction of NaOH with CO2 (carbon dioxide). At the same time the NaOH solution is pulling water out of the air, it is also reacting with CO2 to make Na2CO3 (sodium carbonate, washing soda). This chemical reaction will also lower the concentration of the NaOH solution. I decided to keep my explanation simple for the sake of clarity.
** R. H. Stokes and Robinson R. A. Standard Solutions for Humidity Control at 25 C.
Ind. Eng. Chem. 1949, Vol 41, Issue 9.
https://pubs.acs.org/doi/abs/10.1021/ie50477a041
This has been edited and updated for accuracy and clarity.